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AQA GCSE Chemistry Smart practice A mixed round aimed at your weak spots
Unit 1
Atomic structure and the periodic table
Unit 2
Bonding, structure, and the properties of matter
Unit 3
Quantitative chemistry
Unit 4
Chemical changes
Unit 5
Energy changes
Unit 6
The rate and extent of chemical change
Unit 7
Organic chemistry
Unit 8
Chemical analysis
Unit 9
Chemistry of the atmosphere
Unit 10
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Production and uses of NPK fertilisers (chemistry only)

Practise 30 exam-style questions on Production and uses of NPK fertilisers (chemistry only) for AQA GCSE Chemistry. Write your answer as you would in the exam and get it marked in seconds against the mark scheme, point by point, with an AI tutor on hand if you get stuck.

  • 30 questions
  • 1–6 marks each
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20 questions, marked as you go

Sample questions with model answers

Here are 4 of the questions in this topic, each with a model answer, an explanation of why it earns the marks and the mark scheme an examiner would use.

Question 1

2 marks

NPK fertilisers contain compounds of three elements.

Name the three elements.

Model answer

Nitrogen, phosphorus and potassium.

Explanation

N, P and K are the chemical symbols of nitrogen, phosphorus and potassium. Be careful: P is phosphorus, and K (not P) is potassium.

Mark scheme
  1. 1 mark

    any two of: nitrogen, phosphorus, potassium

    do not accept the symbols N, P and K alone; ignore nitrate, phosphate

  2. 1 mark

    all three correct: nitrogen, phosphorus and potassium

Question 2

2 marks

Triple superphosphate is made by treating phosphate rock with phosphoric acid. Single superphosphate is made by treating phosphate rock with sulfuric acid.

Explain why triple superphosphate contains a higher percentage of phosphorus than single superphosphate.

Model answer

Single superphosphate is a mixture of calcium phosphate and calcium sulfate. The calcium sulfate contains no phosphorus, so it dilutes the phosphate. Triple superphosphate is just calcium phosphate, and the phosphoric acid also adds phosphorus.

Explanation

The acid used decides what else ends up in the product. Phosphoric acid contributes phosphorus itself and produces no calcium sulfate, so the product is richer in phosphorus.

Mark scheme
  1. 1 mark

    single superphosphate also contains calcium sulfate

  2. 1 mark

    which contains no phosphorus / dilutes the calcium phosphate

    allow phosphoric acid adds extra phosphorus to triple superphosphate

Question 3

3 marks

NPK fertilisers improve agricultural productivity.

Explain how using NPK fertilisers allows farmers to produce more food.

Model answer

As crops grow, they remove compounds of nitrogen, phosphorus and potassium from the soil. NPK fertilisers replace these elements in soluble forms that plants can absorb, so the crops grow faster and bigger. This gives a higher yield, so more food is produced from the same area of land.

Explanation

Without fertilisers, soil becomes depleted of the elements crops need and yields fall. Fertilisers let farmers grow more food on the land they have.

Mark scheme
  1. 1 mark

    crops remove nitrogen, phosphorus and potassium from the soil (as they grow)

    max 3

  2. 1 mark

    fertilisers replace these elements / provide them in a soluble form that plants can absorb

  3. 1 mark

    so crops grow faster / bigger, giving a higher yield

  4. 1 mark

    so more food is produced from the same area of land

Question 4

4 marks

A student titrates 25.0 cm³ of ammonia solution with sulfuric acid of concentration 0.100 mol/dm³. The ammonia is exactly neutralised by 20.0 cm³ of the acid.
2NH₃ + H₂SO₄ → (NH₄)₂SO₄

Calculate the concentration of the ammonia solution in mol/dm³.

Model answer

moles of H₂SO₄ = 0.100 × (20.0 ÷ 1000) = 0.00200 mol
moles of NH₃ = 2 × 0.00200 = 0.00400 mol
concentration of NH₃ = 0.00400 ÷ (25.0 ÷ 1000) = 0.160 mol/dm³

Explanation

Convert volumes from cm³ to dm³ by dividing by 1000. The equation shows two moles of ammonia react with each mole of sulfuric acid, so double the moles of acid before dividing by the volume of ammonia.

Mark scheme
  1. 1 mark

    moles of H₂SO₄ = 0.100 × 20.0 ÷ 1000 = 0.00200 (mol)

  2. 1 mark

    moles of NH₃ = 2 × 0.00200 = 0.00400 (mol)

    allow ecf

  3. 1 mark

    concentration = 0.00400 ÷ (25.0 ÷ 1000)

    allow ecf

  4. 1 mark

    = 0.160 (mol/dm³)

    allow 0.16; correct answer with no working scores 4 marks; 0.0800 (ratio not used) scores 3 marks

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