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AQA GCSE Chemistry Smart practice A mixed round aimed at your weak spots
Unit 1
Atomic structure and the periodic table
Unit 2
Bonding, structure, and the properties of matter
Unit 3
Quantitative chemistry
Unit 4
Chemical changes
Unit 5
Energy changes
Unit 6
The rate and extent of chemical change
Unit 7
Organic chemistry
Unit 8
Chemical analysis
Unit 9
Chemistry of the atmosphere
Unit 10
Using resources
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Metal oxides

Practise 13 exam-style questions on Metal oxides for AQA GCSE Chemistry. Write your answer as you would in the exam and get it marked in seconds against the mark scheme, point by point, with an AI tutor on hand if you get stuck.

  • 13 questions
  • 1–6 marks each
  • Instant marking
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13 questions, marked as you go

Sample questions with model answers

Here are 4 of the questions in this topic, each with a model answer, an explanation of why it earns the marks and the mark scheme an examiner would use.

Question 1

2 marks

Magnesium burns in oxygen with a bright white flame to produce magnesium oxide.

Write a balanced symbol equation for this reaction.

Model answer

2Mg + O₂ → 2MgO

Explanation

Oxygen is diatomic, so it must be written as O₂. Magnesium ions are Mg²⁺ and oxide ions are O²⁻, so magnesium oxide is MgO; two MgO are needed to use both oxygen atoms, so two Mg atoms are needed too.

Mark scheme
  1. 1 mark

    correct formulae: Mg + O₂ → MgO

    do not accept O instead of O₂

  2. 1 mark

    balanced: 2Mg + O₂ → 2MgO

    allow multiples; ignore state symbols

Question 2

2 marks

Iron slowly reacts with oxygen to form iron(III) oxide, Fe₂O₃.

Write a balanced symbol equation for this reaction.

Model answer

4Fe + 3O₂ → 2Fe₂O₃

Explanation

Balance the oxygen first: Fe₂O₃ has 3 oxygen atoms and O₂ has 2, so use 2Fe₂O₃ (6 oxygen atoms) and 3O₂. Two Fe₂O₃ contain 4 iron atoms, so 4Fe is needed.

Mark scheme
  1. 1 mark

    correct formulae: Fe + O₂ → Fe₂O₃

  2. 1 mark

    balanced: 4Fe + 3O₂ → 2Fe₂O₃

    allow multiples; ignore state symbols

Question 3

3 marks

A student investigated how some metals react with oxygen. The table shows the student's observations.

Use the observations to place the five metals in order of reactivity, starting with the most reactive. Explain how you decided.

Table with columns "Metal", "Observation". Metal: copper; Observation: surface turns black when heated; does not burn | Metal: gold; Observation: no change, even when heated strongly | Metal: iron wool; Observation: glows and gives off sparks when heated | Metal: magnesium; Observation: burns with a bright white flame when heated | Metal: sodium; Observation: goes dull at room temperature; burns when warmed.

Model answer

Sodium, magnesium, iron, copper, gold. Sodium reacts with oxygen even without heating, so it is the most reactive. Magnesium burns brightly but needs heating, iron only glows and sparks, copper just forms a black coating and gold does not react at all, so the more vigorous the reaction, the more reactive the metal.

Explanation

More reactive metals react with oxygen more readily and more vigorously. Reacting at room temperature shows very high reactivity, while needing strong heating, forming only a surface coating or not reacting at all shows lower reactivity.

Mark scheme
  1. 1 mark

    sodium (first, most reactive) and gold (last, least reactive)

    correct full order is sodium, magnesium, iron, copper, gold

  2. 1 mark

    magnesium, iron, copper in that order (in the middle)

  3. 1 mark

    the more reactive the metal, the more vigorously it reacts / the less heating it needs to react with oxygen

    allow sodium reacts without heating so it is the most reactive; gold does not react so it is the least reactive

Question 4

4 marks

When hydrogen gas is passed over heated copper(II) oxide, copper and water are produced:
CuO + H₂ → Cu + H₂O

Identify the substance that is oxidised and the substance that is reduced in this reaction. Explain your answers in terms of oxygen.

Model answer

Hydrogen is oxidised because it gains oxygen to form water. Copper(II) oxide is reduced because it loses oxygen to form copper.

Explanation

Oxidation and reduction always happen together: the oxygen removed from the copper(II) oxide is gained by the hydrogen. Be careful to name the compound copper(II) oxide as the substance reduced, not 'copper', because copper is the product.

Mark scheme
  1. 1 mark

    hydrogen is oxidised

    allow H₂

  2. 1 mark

    because hydrogen gains oxygen (to form water)

  3. 1 mark

    copper(II) oxide is reduced

    allow copper oxide or CuO; do not accept copper

  4. 1 mark

    because copper(II) oxide loses oxygen (to form copper)

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