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AQA GCSE Physics Smart practice A mixed round aimed at your weak spots
Unit 1
Energy
Energy changes in a system, and the ways energy is stored before and after such changes
Energy stores and systems
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Changes in energy
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Energy changes in systems
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Power
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Conservation and dissipation of energy
Energy transfers in a system
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Efficiency
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Unit 2
Electricity
Unit 3
Particle model of matter
Unit 4
Atomic structure
Unit 5
Forces
Unit 6
Waves
Unit 7
Magnetism and electromagnetism
Unit 8
Space physics (physics only)
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Our solar system

Practise 31 exam-style questions on Our solar system for AQA GCSE Physics. Write your answer as you would in the exam and get it marked in seconds against the mark scheme, point by point, with an AI tutor on hand if you get stuck.

  • 31 questions
  • 1–6 marks each
  • Instant marking
  • No sign-up needed
20 questions, marked as you go

Sample questions with model answers

Here are 4 of the questions in this topic, each with a model answer, an explanation of why it earns the marks and the mark scheme an examiner would use.

Question 1

2 marks

Name the star at the centre of our solar system and state how many planets orbit it.

Model answer

The Sun. Eight planets orbit it.

Explanation

Our solar system has only one star, the Sun. Eight planets orbit it: Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus and Neptune. Pluto is now classed as a dwarf planet, so it is not counted.

Mark scheme
  1. 1 mark

    the Sun

  2. 1 mark

    eight (planets)

    allow 8; do not accept nine

Question 2

2 marks

Give one similarity and one difference between a planet and a dwarf planet.

Model answer

Similarity: both planets and dwarf planets orbit the Sun. Difference: dwarf planets are much smaller than planets.

Explanation

Dwarf planets such as Pluto and Ceres orbit the Sun just like planets, but they are much smaller and share their orbits with many other objects. Moons are different again because they orbit planets.

Mark scheme
  1. 1 mark

    similarity: both orbit the Sun

    allow both are (roughly spherical) natural objects in the solar system; allow both can have moons

  2. 1 mark

    difference: dwarf planets are (much) smaller (than planets)

    allow dwarf planets have not cleared other objects from their orbits

Question 3

3 marks

The Sun is in equilibrium now, but it will not stay in equilibrium forever.

Explain why.

Model answer

The Sun is fusing hydrogen in its core, and eventually the hydrogen there will run out. Hydrogen fusion in the core will then stop, so the outward force due to fusion energy will no longer balance the inward pull of gravity. The balance is lost and the Sun will change: its core will contract while its outer layers expand, and it will become a red giant.

Explanation

Equilibrium only lasts while there is fuel for fusion. The Sun has enough hydrogen for about 10 billion years in total, and is roughly halfway through its main sequence stage.

Mark scheme
  1. 1 mark

    the hydrogen in the core will eventually run out / be used up

  2. 1 mark

    so hydrogen fusion in the core stops and the outward force no longer balances gravity

    allow energy release changes so the forces are unbalanced

  3. 1 mark

    so the star changes size (the core contracts and the outer layers expand into a red giant)

    allow the Sun will become a red giant

Question 4

4 marks

The mean distance from the Sun to the Earth is 150 million km. Light travels at 3.0 × 10⁸ m/s.

Calculate the time taken for light to travel from the Sun to the Earth.
Give your answer in minutes.

Model answer

distance = 150 million km = 150 × 10⁶ × 1000 m = 1.5 × 10¹¹ m
distance = speed × time
1.5 × 10¹¹ = 3.0 × 10⁸ × t
t = 1.5 × 10¹¹ ÷ 3.0 × 10⁸ = 500 s
500 ÷ 60 = 8.3 minutes

Explanation

Convert million kilometres to metres carefully: 1 million km = 10⁶ km = 10⁹ m. Even at the speed of light, sunlight takes over 8 minutes to reach us, which shows how large the solar system is.

Mark scheme
  1. 1 mark

    150 million km = 1.5 × 10¹¹ m

    an answer of 8.3 (minutes) scores 4 marks

  2. 1 mark

    1.5 × 10¹¹ = 3.0 × 10⁸ × t

    allow t = 1.5 × 10¹¹ ÷ 3.0 × 10⁸; allow ecf from an incorrect conversion

  3. 1 mark

    t = 500 (s)

    allow ecf

  4. 1 mark

    500 ÷ 60 = 8.3 (minutes)

    allow 8.33 / 8 min 20 s; allow ecf

Ready to try the rest? Every answer you write is marked against the mark scheme, so you can see exactly where the marks are.

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