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AQA GCSE Physics Smart practice A mixed round aimed at your weak spots
Unit 1
Energy
Energy changes in a system, and the ways energy is stored before and after such changes
Energy stores and systems
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Changes in energy
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Power
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Conservation and dissipation of energy
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Unit 2
Electricity
Unit 3
Particle model of matter
Unit 4
Atomic structure
Unit 5
Forces
Unit 6
Waves
Unit 7
Magnetism and electromagnetism
Unit 8
Space physics (physics only)
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Mains electricity

Practise 32 exam-style questions on Mains electricity for AQA GCSE Physics. Write your answer as you would in the exam and get it marked in seconds against the mark scheme, point by point, with an AI tutor on hand if you get stuck.

  • 32 questions
  • 1–6 marks each
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20 questions, marked as you go

Sample questions with model answers

Here are 4 of the questions in this topic, each with a model answer, an explanation of why it earns the marks and the mark scheme an examiner would use.

Question 1

2 marks

Describe the function of the neutral wire in a mains circuit.

Model answer

The neutral wire completes the circuit, so the current can flow from the live wire, through the appliance and back along the neutral wire. It is at, or close to, earth potential (0 V).

Explanation

An appliance needs a complete circuit. The live wire provides the alternating potential difference and the neutral wire provides the return path. In normal use the earth wire carries no current at all.

Mark scheme
  1. 1 mark

    it completes the circuit

    allow it carries the current back from the appliance

  2. 1 mark

    it is at, or close to, earth potential (0 V)

Question 2

2 marks

An electrician uses a tester and finds that one wire in a cable has a potential difference of 230 V relative to earth.

Name this wire and give the colour its insulation should be.

Model answer

It is the live wire, and its insulation should be brown.

Explanation

Only the live wire is at about 230 V relative to earth. The neutral (blue) is at or close to 0 V and the earth wire (green and yellow) is at 0 V.

Mark scheme
  1. 1 mark

    the live wire

  2. 1 mark

    brown

Question 3

3 marks

An electrician measures the potential difference between pairs of wires in a correctly wired mains circuit. The table shows the results.

Give the values of X and Y. Explain the value of Y.

Table with columns "Pair of wires", "Potential difference in V". Pair of wires: Live and earth; Potential difference in V: 230 | Pair of wires: Live and neutral; Potential difference in V: X | Pair of wires: Neutral and earth; Potential difference in V: Y.

Model answer

X = 230 V and Y = 0 V.
Y is zero because the neutral wire is at, or close to, earth potential (0 V), and the earth wire is also at 0 V, so there is (almost) no potential difference between them.

Explanation

The live wire is at about 230 V relative to earth. Because the neutral wire is at about 0 V, the potential difference between live and neutral is also about 230 V.

Mark scheme
  1. 1 mark

    X = 230 (V)

    allow about 230 (V)

  2. 1 mark

    Y = 0 (V)

    allow close to 0 (V)

  3. 1 mark

    the neutral wire is at, or close to, earth potential (0 V), and the earth wire is at 0 V

Question 4

4 marks

A person with a body resistance of 2.3 kΩ touches a bare live wire while standing on the ground.

Calculate the current through the person. A current of about 0.05 A through the body can be fatal. Use your answer to comment on the danger.

Model answer

The person is at earth potential (0 V) and the live wire is at 230 V, so the potential difference across them is 230 V.
R = 2.3 kΩ = 2300 Ω
I = V ÷ R = 230 ÷ 2300 = 0.10 A
This is twice the current of 0.05 A that can be fatal, so touching the live wire could kill.

Explanation

The connection between the live wire and earth through the body is the danger. Any increase in the resistance of that path (dry skin, rubber soles) reduces the current; wet skin reduces the resistance and makes it worse.

Mark scheme
  1. 1 mark

    the potential difference across the person is 230 V (because they are at earth potential, 0 V)

  2. 1 mark

    I = 230 ÷ 2300

    allow 230 = I × 2300; allow ecf from an incorrect p.d. or conversion

  3. 1 mark

    0.10 (A)

    allow 0.1 (A); an answer of 100 (A) (kΩ not converted) scores 1 mark for this and the previous point

  4. 1 mark

    0.10 A is twice the current that can be fatal, so the shock could kill

    allow ecf: compare their current with 0.05 A

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