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AQA GCSE Physics Smart practice A mixed round aimed at your weak spots
Unit 1
Energy
Energy changes in a system, and the ways energy is stored before and after such changes
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Unit 2
Electricity
Unit 3
Particle model of matter
Unit 4
Atomic structure
Unit 5
Forces
Unit 6
Waves
Unit 7
Magnetism and electromagnetism
Unit 8
Space physics (physics only)
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Distance and displacement

Practise 23 exam-style questions on Distance and displacement for AQA GCSE Physics. Write your answer as you would in the exam and get it marked in seconds against the mark scheme, point by point, with an AI tutor on hand if you get stuck.

  • 23 questions
  • 1–6 marks each
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20 questions, marked as you go

Sample questions with model answers

Here are 4 of the questions in this topic, each with a model answer, an explanation of why it earns the marks and the mark scheme an examiner would use.

Question 1

1 mark

Name one vector quantity, other than displacement.

Model answer

Velocity.

Explanation

A vector quantity has both magnitude and direction. Velocity, acceleration, force and momentum are all vectors; speed is the scalar partner of velocity, just as distance is the scalar partner of displacement.

Mark scheme
  1. 1 mark

    any one from: velocity, acceleration, force, weight, momentum

    allow any named force, e.g. friction, drag, upthrust; do not accept speed, distance, mass, energy or time

Question 2

2 marks

A car's odometer records how far the car has travelled.

Explain why the odometer shows the distance travelled and not the displacement.

Model answer

The odometer adds up the total length of road the car has travelled along, for example by counting the turns of the wheels. It ignores direction, so the reading keeps increasing even if the car turns round and drives back towards where it started.

Explanation

Distance is a scalar that just adds up path length. A displacement meter would need to know the car's straight-line position and direction from the start, and would read zero after a round trip.

Mark scheme
  1. 1 mark

    it measures the total length of the path travelled (e.g. from the number of turns of the wheels)

  2. 1 mark

    it does not take account of direction / the reading keeps increasing even when the car turns back

    allow it would not return to zero when the car returns to its starting point

Question 3

3 marks

Explain why the distance travelled by an object can never be less than the size (magnitude) of its displacement.

Model answer

The size of the displacement is the straight-line distance between the start point and the finish point. A straight line is the shortest possible path between two points, so any route that bends or changes direction is longer. The distance is therefore always greater than or equal to the size of the displacement, and they are only equal when the object moves in a straight line without turning back.

Explanation

This is a useful check on answers: if you calculate a displacement bigger than the distance travelled, something has gone wrong. Round trips are the extreme case, with a large distance and zero displacement.

Mark scheme
  1. 1 mark

    displacement is measured along the straight line from the start point to the finish point

  2. 1 mark

    a straight line is the shortest path between two points

  3. 1 mark

    so any other path / any change of direction makes the distance greater; they are equal only for motion in a straight line in one direction

Question 4

4 marks

A Ferris wheel has a diameter of 50 m. A passenger gets on at the bottom of the wheel and travels half a turn to the top.

Calculate the distance travelled by the passenger and state the passenger's displacement.

Model answer

Circumference = π × diameter = π × 50 = 157 m
Distance = half the circumference = 157 ÷ 2 = 78.5 m
Displacement = 50 m vertically upwards (the diameter of the wheel)

Explanation

The passenger travels along a semicircle, so the distance is half the circumference. The displacement is the straight line from the bottom of the wheel to the top, which is the diameter, and its direction is vertically upwards.

Mark scheme
  1. 1 mark

    distance = half the circumference = (π × 50) ÷ 2

    allow π × 25; correct answer with no working scores full marks

  2. 1 mark

    distance = 78.5 m

    allow 79 m; allow 78.5-78.6 m

  3. 1 mark

    displacement = 50 m

  4. 1 mark

    vertically upwards

    direction mark

Ready to try the rest? Every answer you write is marked against the mark scheme, so you can see exactly where the marks are.

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