Practise 20 exam-style questions on Units of measure for Edexcel GCSE Maths (Non-calculator). Write your answer as you would in the exam and get it marked in seconds against the mark scheme, point by point, with an AI tutor on hand if you get stuck.
20 questions
1–5 marks each
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20 questions, marked as you go
Sample questions with model answers
Here are 4 of the questions in this topic, each with a model answer, an explanation of why it earns the marks and the mark scheme an examiner would use.
Question 1
2 marks
A car travels at a constant speed of 72 km/h.
Change this speed into metres per second.
Model answer
72 km/h = 72 000 m in 1 hour 1 hour = 3600 seconds \(72\,000 \div 3600 = 20\) m/s
Explanation
Change the distance into metres (× 1000) and the time into seconds (1 hour = 60 × 60 = 3600 s), then divide. Overall this is the same as dividing a speed in km/h by 3.6.
Mark scheme
1 mark
M1 for \(72 \times 1000 \div 3600\) or \(72\,000 \div 3600\) or \(72 \div 3.6\)
oe, e.g. 72 000 m in 60 minutes so 1200 m per minute; correct answer with no working scores full marks
1 mark
A1 for 20 (m/s)
cao
Question 2
2 marks
Show that 1 km² = \(1 \times 10^{12}\) mm².
Model answer
1 km = 1000 m = 100 000 cm = 1 000 000 mm \(= 10^6\) mm 1 km² = \(10^6\) mm × \(10^6\) mm \(= 10^{12}\) mm²
Explanation
First find how many millimetres are in a kilometre, then square that factor because area is two-dimensional. Using index laws, \((10^6)^2 = 10^{12}\).
Mark scheme
1 mark
M1 for 1 km = \(10^6\) mm (1 000 000 mm)
e.g. \(1000 \times 100 \times 10\)
1 mark
C1 for \((10^6)^2 = 10^{12}\) so 1 km² = \(10^6 \times 10^6 = 10^{12}\) mm²
answer only scores 0 (show that)
Question 3
3 marks
A gold bar is a cuboid measuring 20 cm by 5 cm by 4 cm. The density of gold is 19.3 g/cm³.
Work out the mass of the gold bar. Give your answer in kilograms.
Model answer
Volume \(= 20 \times 5 \times 4 = 400\) cm³ Mass = density × volume \(= 19.3 \times 400 = 7720\) g \(7720 \div 1000 = 7.72\) kg
Explanation
Mass = density × volume, with the volume in cm³ to match the density in g/cm³. The answer comes out in grams, so divide by 1000 to give kilograms.
Tom is paid £12.60 for each hour he works. Each day he starts work at 08:45 and finishes at 17:15. He has a 45-minute lunch break, which is not paid. He works 5 days each week.
Work out how much Tom is paid each week.
Model answer
08:45 to 17:15 = 8 hours 30 minutes Paid time each day = 8 h 30 min − 45 min = 7 hours 45 minutes = 7.75 hours Pay each day \(= 7.75 \times 12.60 = 88.20 + 9.45 = £97.65\) Pay each week \(= 5 \times 97.65 = £488.25\)
Explanation
Work in hours and minutes first, then change 45 minutes into 0.75 of an hour before multiplying by the hourly rate. Writing 7 hours 45 minutes as 7.45 hours is a common error.
Mark scheme
1 mark
M1 for 8 hours 30 minutes from 08:45 to 17:15
correct answer with no working scores full marks
1 mark
M1 for 7 hours 45 minutes paid each day, or 7.75 hours (or 465 minutes)
1 mark
M1 for \(7.75 \times 12.60 \times 5\)
oe, e.g. \(38.75 \times 12.60\); do not accept 7.45 used as hours
1 mark
A1 for £488.25
cao
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