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Edexcel GCSE Maths (Non-calculator) Smart practice A mixed round aimed at your weak spots
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Number
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Algebra
Unit 3
Ratio, proportion and rates of change
Unit 4
Geometry and measures
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Probability
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Statistics
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Transformations

Practise 28 exam-style questions on Transformations for Edexcel GCSE Maths (Non-calculator). Write your answer as you would in the exam and get it marked in seconds against the mark scheme, point by point, with an AI tutor on hand if you get stuck.

  • 28 questions
  • 1–5 marks each
  • Instant marking
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20 questions, marked as you go

Sample questions with model answers

Here are 4 of the questions in this topic, each with a model answer, an explanation of why it earns the marks and the mark scheme an examiner would use.

Question 1

2 marks

The grid below shows shape P and shape Q.

Describe fully the single transformation that maps shape P onto shape Q.

A coordinate grid with x from −6 to 4 and y from −1 to 5; each grid square is 1 unit across, and the axes cross at the origin O. Shape P is a shaded quadrilateral with vertices (1, 1), (3, 1), (3, 2) and (2, 4). Shape Q is a shaded quadrilateral with vertices (−3, 1), (−5, 1), (−5, 2) and (−4, 4).

Model answer

Reflection in the line \(x = -1\)

Explanation

Q is a mirror image of P, so the transformation is a reflection. Corresponding points such as (1, 1) and (−3, 1) are the same distance either side of the mirror line, so it lies halfway between them, at x = −1. A full description must give the equation of the mirror line.

Mark scheme
  1. 1 mark

    B1 for reflection

  2. 1 mark

    B1 for in the line \(x = -1\)

    B0 for any second transformation

Question 2

2 marks

A shape is rotated through 180°.
The point (1, 2) on the shape maps to the point (5, 6).

Find the coordinates of the centre of rotation.

Model answer

For a half turn, the centre is the midpoint of each point and its image.
Centre = \(\left(\dfrac{1 + 5}{2}, \dfrac{2 + 6}{2}\right) = (3, 4)\)

Explanation

A rotation of 180° sends each point straight through the centre to the same distance on the other side. So the centre is exactly halfway between a point and its image.

Mark scheme
  1. 1 mark

    M1 for finding the midpoint of (1, 2) and (5, 6)

    correct answer with no working scores full marks

  2. 1 mark

    A1 for (3, 4)

    cao

Question 3

3 marks

The diagram shows triangles M and N on a grid.

Describe fully the single transformation that maps triangle M onto triangle N.

A coordinate grid with x from −4 to 4 and y from −1 to 5; each grid square is 1 unit across, and the axes cross at the origin O. Shape M is a shaded triangle with vertices (−2, 1), (0, 1) and (−2, 2). Shape N is a shaded triangle with vertices (−1, 2), (3, 2) and (−1, 4).

Model answer

Enlargement, scale factor 2, centre (−3, 0)

Explanation

The sides of N are twice as long as those of M and face the same way, so it is an enlargement with scale factor 2. Draw lines through corresponding vertices, e.g. (0, 1) to (3, 2) and (−2, 1) to (−1, 2); they meet at the centre, (−3, 0).

Mark scheme
  1. 1 mark

    B1 for enlargement

  2. 1 mark

    B1 for scale factor 2

  3. 1 mark

    B1 for centre (−3, 0)

    B0 overall for any second transformation

Question 4

3 marks

A shape is enlarged by scale factor −2, with centre (2, 3).
The image of the point P is the point (−4, 7).

Find the coordinates of P.

Model answer

From the centre (2, 3) to the image (−4, 7): \(\begin{pmatrix}-6\\4\end{pmatrix}\)
This is −2 times the vector from the centre to P, so the vector to P is \(\begin{pmatrix}-6\\4\end{pmatrix} \div (-2) = \begin{pmatrix}3\\-2\end{pmatrix}\)
P = (2 + 3, 3 − 2) = (5, 1)

Explanation

Work backwards: the image vector from the centre is the object vector multiplied by −2, so divide by −2 to undo it. Check: from (2, 3) to (5, 1) is (3, −2); times −2 gives (−6, 4), which reaches (−4, 7).

Mark scheme
  1. 1 mark

    M1 for the vector from the centre to the image, \(\begin{pmatrix}-6\\4\end{pmatrix}\)

    correct answer with no working scores full marks

  2. 1 mark

    M1 for dividing by −2, giving \(\begin{pmatrix}3\\-2\end{pmatrix}\)

  3. 1 mark

    A1 for (5, 1)

    cao

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