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Edexcel GCSE Maths (Non-calculator) Smart practice A mixed round aimed at your weak spots
Unit 1
Number
Unit 2
Algebra
Unit 3
Ratio, proportion and rates of change
Unit 4
Geometry and measures
Unit 5
Probability
Unit 6
Statistics
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Order of operations and inverse operations

Practise 21 exam-style questions on Order of operations and inverse operations for Edexcel GCSE Maths (Non-calculator). Write your answer as you would in the exam and get it marked in seconds against the mark scheme, point by point, with an AI tutor on hand if you get stuck.

  • 21 questions
  • 1–5 marks each
  • Instant marking
  • No sign-up needed
20 questions, marked as you go

Sample questions with model answers

Here are 4 of the questions in this topic, each with a model answer, an explanation of why it earns the marks and the mark scheme an examiner would use.

Question 1

2 marks

Put brackets into each calculation to make it correct. You may use more than one pair of brackets in a calculation.

8 − 2 × 3 + 1 = 24

\(3 + 2^2 \times 5 - 1 = 100\)

Model answer

(8 − 2) × (3 + 1) = 6 × 4 = 24
\((3 + 2)^2 \times (5 - 1) = 25 \times 4 = 100\)

Explanation

Brackets are worked out first, so they change the order of operations. Try putting brackets round an addition or subtraction so that it happens before the multiplication. In the second calculation, \((3 + 2)^2\) squares 5, not just 2.

Mark scheme
  1. 1 mark

    B1 for (8 − 2) × (3 + 1) = 24

    cao; correct answer with no working scores full marks

  2. 1 mark

    B1 for \((3 + 2)^2 \times (5 - 1) = 100\)

Question 2

2 marks

Ravi thinks of a number.
He squares the number, then subtracts 7, then divides by 3.
His answer is 14.

Find the two numbers Ravi could have thought of.

Model answer

Work backwards, using inverse operations in reverse order:
14 × 3 = 42
42 + 7 = 49
\(\sqrt{49} = 7\) or \(-7\)
Ravi's number was 7 or −7.

Explanation

To undo a sequence of operations, apply the inverse operations in the reverse order: × 3 undoes ÷ 3, + 7 undoes − 7, and square root undoes squaring. Remember that both 7 and −7 square to 49.

Mark scheme
  1. 1 mark

    M1 for working backwards with inverse operations in the correct order, e.g. 14 × 3 + 7 (= 49)

    or an equation such as \(\dfrac{x^2 - 7}{3} = 14\); correct answer with no working scores full marks

  2. 1 mark

    A1 for 7 and −7

    both needed

Question 3

3 marks

Work out
\[\dfrac{48 \times 35 \times 0.2}{14 \times 0.6}\]

Model answer

Cancel common factors:
\(\dfrac{35}{14} = \dfrac{5}{2}\) and \(\dfrac{0.2}{0.6} = \dfrac{1}{3}\)
So the calculation is \(48 \times \dfrac{5}{2} \times \dfrac{1}{3} = \dfrac{240}{6} = 40\)

Explanation

Multiplication and division are inverse operations, so a factor on the top cancels with the same factor on the bottom. Cancelling first keeps the numbers small. Working it out directly also works: 48 × 35 × 0.2 = 336 and 14 × 0.6 = 8.4, and 336 ÷ 8.4 = 3360 ÷ 84 = 40.

Mark scheme
  1. 1 mark

    M1 for a correct first cancellation or evaluation, e.g. \(\dfrac{35}{14} = \dfrac{5}{2}\), \(\dfrac{0.2}{0.6} = \dfrac{1}{3}\), numerator 336 or denominator 8.4

    correct answer with no working scores full marks

  2. 1 mark

    M1 for a complete method, e.g. \(48 \times \dfrac{5}{2} \times \dfrac{1}{3}\), or 336 ÷ 8.4

  3. 1 mark

    A1 for 40

    cao

Question 4

4 marks

On each of three days, Fiona spends half of the money she has and then spends another £4.
At the end of the third day she has £1 left.

How much money did Fiona have at the start of the first day?

Model answer

Work backwards. To undo 'halve, then subtract 4', add 4 and then double.
Start of day 3: (1 + 4) × 2 = £10
Start of day 2: (10 + 4) × 2 = £28
Start of day 1: (28 + 4) × 2 = £64
Check: 64 → 32 − 4 = 28 → 14 − 4 = 10 → 5 − 4 = 1

Explanation

Each day the operations are 'halve' then 'subtract 4', so going backwards you must undo them in the reverse order: add 4 first, then double. Doubling first and then adding 4 is the most common mistake. Always check by working forwards.

Mark scheme
  1. 1 mark

    P1 for reversing one day correctly: add 4 then multiply by 2, e.g. (1 + 4) × 2 = 10

    or a correct forward trial for a starting amount, showing all three days; correct answer with no working scores full marks

  2. 1 mark

    P1 for £10 at the start of day 3 and (10 + 4) × 2 = £28 at the start of day 2

  3. 1 mark

    P1 for (28 + 4) × 2

    ft their value for the start of day 2

  4. 1 mark

    A1 for £64

    cao

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