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Edexcel GCSE Maths (Non-calculator) Smart practice A mixed round aimed at your weak spots
Unit 1
Number
Unit 2
Algebra
Unit 3
Ratio, proportion and rates of change
Unit 4
Geometry and measures
Unit 5
Probability
Unit 6
Statistics
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Properties of 3D shapes

Practise 19 exam-style questions on Properties of 3D shapes for Edexcel GCSE Maths (Non-calculator). Write your answer as you would in the exam and get it marked in seconds against the mark scheme, point by point, with an AI tutor on hand if you get stuck.

  • 19 questions
  • 1–5 marks each
  • Instant marking
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19 questions, marked as you go

Sample questions with model answers

Here are 4 of the questions in this topic, each with a model answer, an explanation of why it earns the marks and the mark scheme an examiner would use.

Question 1

2 marks

The diagram shows a triangular prism.

Write down the number of faces, the number of edges and the number of vertices of the prism.

A triangular prism drawn in 3D with hidden edges shown as dashed lines. Its end is an isosceles triangle. The base of the triangle is labelled 6 cm (along the bottom edge of the front triangle). The height of the triangle is labelled 4 cm (on a dashed line from the top vertex of the front triangle down to its base, at right angles to the base). The length of the prism is labelled 10 cm (along the bottom edge going back from the front triangle). The diagram is labelled "Diagram NOT accurately drawn".

Model answer

Faces: 5 (2 triangles and 3 rectangles)
Edges: 9 (3 on each triangle and 3 joining them)
Vertices: 6

Explanation

Count systematically: a prism has two end faces plus one rectangular face for each side of the cross-section. Each triangular end has 3 edges and 3 vertices, and 3 more edges join the two ends.

Mark scheme
  1. 1 mark

    B1 for two of: 5 faces, 9 edges, 6 vertices

  2. 1 mark

    B1 for all three correct: 5 faces, 9 edges, 6 vertices

    all three correct scores 2 marks

Question 2

2 marks

Explain why the number of edges of any prism is a multiple of 3.

Model answer

Let the cross-section of the prism have \(n\) sides.
Each of the two end faces has \(n\) edges: \(2n\) edges.
Each vertex of one end is joined to the matching vertex of the other end: \(n\) more edges.
Total \(= 2n + n = 3n\), which is always a multiple of 3.

Explanation

An explanation must work for every prism, so use \(n\) for the number of sides of the cross-section rather than checking one example. The edges come in three groups of \(n\).

Mark scheme
  1. 1 mark

    M1 for using a cross-section with \(n\) sides: \(n\) edges on each end face and \(n\) edges joining the two ends

    oe in words

  2. 1 mark

    C1 for total \(n + n + n = 3n\), which is a multiple of 3

    a numerical example alone scores 0

Question 3

3 marks

A regular tetrahedron is a triangular-based pyramid whose four faces are all equilateral triangles.
Every edge of a regular tetrahedron is 4 cm long.

Work out the exact total surface area of the tetrahedron.

Model answer

Area of one face \(= \frac{1}{2} \times 4 \times 4 \times \sin 60^\circ = 8 \times \dfrac{\sqrt{3}}{2} = 4\sqrt{3}\) cm²
There are 4 faces.
Total surface area \(= 4 \times 4\sqrt{3} = 16\sqrt{3}\) cm²

Explanation

A tetrahedron has 4 triangular faces, and here they are identical equilateral triangles. Use area \(= \frac{1}{2}ab\sin C\) with the exact value \(\sin 60^\circ = \frac{\sqrt{3}}{2}\), or find the height by Pythagoras' theorem.

Mark scheme
  1. 1 mark

    M1 for the area of one face: \(\frac{1}{2} \times 4 \times 4 \times \sin 60^\circ\) or \(\frac{1}{2} \times 4 \times \sqrt{12}\)

    height of each triangle \(= \sqrt{4^2 - 2^2} = \sqrt{12} = 2\sqrt{3}\); correct answer with no working scores full marks

  2. 1 mark

    M1 for \(4 \times\) their area of one face

  3. 1 mark

    A1 for \(16\sqrt{3}\) (cm²)

    oe, e.g. \(8\sqrt{12}\); do not accept a decimal

Question 4

4 marks

The diagram shows a square-based pyramid.
All 8 edges of the pyramid are 6 cm long.

Work out the exact total surface area of the pyramid.

A square-based pyramid drawn in 3D with hidden edges shown as dashed lines. The length of the base is labelled 6 cm (along the front edge of the base). The length of a sloping edge is labelled 6 cm (along the sloping edge from the apex to the front right corner of the base). The diagram is labelled "Diagram NOT accurately drawn".

Model answer

The faces are one square of side 6 cm and four equilateral triangles of side 6 cm.
Area of square \(= 6^2 = 36\) cm²
Area of one triangle \(= \frac{1}{2} \times 6 \times 6 \times \sin 60^\circ = 18 \times \dfrac{\sqrt{3}}{2} = 9\sqrt{3}\) cm²
Total surface area \(= 36 + 4 \times 9\sqrt{3} = 36 + 36\sqrt{3}\) cm²

Explanation

Because every edge is 6 cm, each sloping face has three 6 cm sides, so it is equilateral. Use the exact value of \(\sin 60^\circ\) (or Pythagoras for the triangle's height) to keep the answer exact.

Mark scheme
  1. 1 mark

    B1 for identifying the faces: one square of side 6 cm and four equilateral triangles of side 6 cm

    may be implied by working

  2. 1 mark

    M1 for the area of one triangle: \(\frac{1}{2} \times 6 \times 6 \times \sin 60^\circ\) or \(\frac{1}{2} \times 6 \times \sqrt{27}\)

    height of each triangle \(= \sqrt{6^2 - 3^2} = \sqrt{27} = 3\sqrt{3}\)

  3. 1 mark

    M1 for \(36 + 4 \times\) their triangle area

  4. 1 mark

    A1 for \(36 + 36\sqrt{3}\) (cm²)

    oe, e.g. \(36(1 + \sqrt{3})\)

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