Question 1
2 marksA student investigated the water potential of parsnip tissue. She placed parsnip cylinders in sucrose solutions with different water potentials for 3 hours, then calculated the percentage change in mass of each cylinder.
The graph shows her results and her line of best fit.
Use the graph to find the water potential of the parsnip tissue. Explain how you obtained your answer.
Model answer
-700 kPa. This is the water potential where the line of best fit crosses 0% change in mass. At this water potential there is no net movement of water by osmosis into or out of the tissue, so the water potential of the tissue equals the water potential of the solution.
Explanation
This is the calibration-curve method of required practical 3: tissue gains mass in solutions with a higher water potential than its own and loses mass in solutions with a lower water potential. The intercept on the x-axis (zero change in mass) gives the solution whose water potential equals that of the tissue. Read the value from the line of best fit, not from the nearest plotted point, and keep the negative sign.
Mark scheme
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1 mark
-700 kPa (accept -680 to -720)
The value must be negative. A value in this range scores this mark with or without an explanation.
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1 mark
Where the line crosses 0% change in mass there is no net movement of water (by osmosis), so the water potential of the tissue equals that of the solution
Accept 'where the line crosses the x-axis' only if linked to no net water movement or to equal water potentials. Insufficient: 'where the line crosses the axis' alone.