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AQA GCSE Biology Smart practice A mixed round aimed at your weak spots
Unit 1
Cell biology
Cell division
Chromosomes
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Mitosis and the cell cycle
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Stem cells
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Cell structure
Animal and plant cells
0%
Cell differentiation
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Cell specialisation
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Culturing microorganisms (biology only)
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Eukaryotes and prokaryotes
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Microscopy
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Transport in cells
Active transport
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Diffusion
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Osmosis
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Unit 2
Organisation
Unit 3
Infection and response
Unit 4
Bioenergetics
Unit 5
Homeostasis and response
Unit 6
Inheritance, variation and evolution
Unit 7
Ecology
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Levels of organisation

Practise 35 exam-style questions on Levels of organisation for AQA GCSE Biology. Write your answer as you would in the exam and get it marked in seconds against the mark scheme, point by point, with an AI tutor on hand if you get stuck.

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  • 3–5 marks each
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20 questions, marked as you go

Sample questions with model answers

Here are 4 of the questions in this topic, each with a model answer, an explanation of why it earns the marks and the mark scheme an examiner would use.

Question 1

3 marks

Describe how quadrat sampling and transect sampling differ and give one situation where each method is preferable.

Model answer

Quadrat sampling estimates abundance/density by counting within repeated square plots; preferable for patchy or even distributions. Transect sampling records species along a line, showing changes with distance; preferable for environmental gradients (shoreline to inland).

Explanation

Quadrats give quantitative abundance measures where species are distributed across an area. Transects are ideal to detect zonation or gradients where conditions change along a line, e.g., from sea to dunes.

Mark scheme
  1. 1 mark

    Quadrat: repeated area samples (counts in squares) to estimate abundance/density

  2. 1 mark

    Transect: sampling along a line to study distribution changes with distance (gradient)

  3. 1 mark

    Use quadrat for estimating abundance in patchy areas; use transect for studying environmental gradients

Question 2

4 marks

Draw a simple food chain of four organisms typical of a pond ecosystem and state which organism is the producer, a primary consumer and a secondary consumer.

Model answer

Algae ? Daphnia ? Small fish ? Heron. Producer: Algae. Primary consumer: Daphnia. Secondary consumer: Small fish.

Explanation

A food chain shows energy flow from producers (make biomass by photosynthesis) to consumers (herbivores then carnivores). In a pond, algae (producer) are eaten by Daphnia (primary consumer), which are eaten by small fish (secondary consumer), sometimes eaten by a heron (tertiary consumer).

Mark scheme
  1. 2 marks

    Correct four-step pond food chain (producer ? primary consumer ? secondary consumer ? tertiary consumer)

    Award 2 marks for correct sequence of four organisms, order matters

  2. 1 mark

    Identify producer correctly

  3. 1 mark

    Identify primary and secondary consumers correctly

    Can be split as 0.5 + 0.5 if needed

Question 3

4 marks

Explain the concept of biomagnification and give one real-world example.

Model answer

Biomagnification is the increase in concentration of persistent toxins up trophic levels because predators accumulate the toxin from their prey. Example: DDT or mercury concentrations increase in fish and are highest in top predators like tuna or eagles.

Explanation

Small organisms pick up toxins; predators eat many contaminated prey, concentrating toxins in their tissues. This can harm top predators and humans consuming contaminated animals.

Mark scheme
  1. 1 mark

    Definition: toxins increase in concentration up the food chain / trophic levels

  2. 1 mark

    Reason: persistent toxins are not metabolised and accumulate in consumers that eat contaminated prey

  3. 1 mark

    Example: DDT, mercury (in aquatic food chains)

    Accept any correct real example

  4. 1 mark

    Consequence: top predators suffer high toxin effects (eg eggshell thinning, poisoning)

Question 4

5 marks

Describe how you would estimate the population size of a mobile animal (e.g., rabbits) in a field using mark–release–recapture. Include formula and two assumptions of the method.

Model answer

Capture and mark a sample M, release and allow mixing, recapture a sample n and count marked recaptures m. Population N ˜ (M × n) / m. Assumptions: marked animals mix randomly and marking does not affect survival or behaviour; no births/deaths/immigration/emigration between samples.

Explanation

Mark–release–recapture uses proportions of marked animals in a second sample to estimate total population, assuming marked individuals represent the whole population and conditions are stable between samplings.

Mark scheme
  1. 1 mark

    Capture and mark first sample (M) and release

  2. 1 mark

    Recapture sample (n) and count marked animals (m)

  3. 1 mark

    Use formula N = (M × n) / m to estimate population

  4. 1 mark

    Assumption 1: marked and unmarked mix randomly and marking does not affect behaviour/survival

  5. 1 mark

    Assumption 2: closed population (no births, deaths, immigration or emigration) between samples

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