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A Method For Simple Cases For Factoring A Quadratic
Simple factorisation for a quadratic
Date : 10/08/2021
A Method For Simple Cases For factoring a QuadraticLuckily there is a method that works in simple cases. With the quadratic equation in this form:
Step 1: Find two numbers that multiply to give ac (in other words a times c), and add to give b.OK, let us try another example: Example: 6x2 + 5x 6 Step 1: ac is 6 ( 6) = 36, and b is 5 List the positive factors of ac = 36: 1, 2, 3, 4, 6, 9, 12, 18, 36One of the numbers has to be negative to make 36, so by playing with a few different numbers I find that 4 and 9 work nicely: 4 9 = 36 and 4+9 = 5 Step 2: Rewrite 5x with 4x and 9x: 6x2 4x + 9x 6 Step 3: Factor first two and last two: 2x(3x 2) + 3(3x 2) Step 4: Common Factor is (3x 2): (2x+3)(3x 2) Check: (2x+3)(3x 2) = 6x2 4x + 9x 6 = 6x2 + 5x 6 (Yes)This resource was uploaded by: Adrian
Step 1: Find two numbers that multiply to give ac (in other words a times c), and add to give b.OK, let us try another example: Example: 6x2 + 5x 6 Step 1: ac is 6 ( 6) = 36, and b is 5 List the positive factors of ac = 36: 1, 2, 3, 4, 6, 9, 12, 18, 36One of the numbers has to be negative to make 36, so by playing with a few different numbers I find that 4 and 9 work nicely: 4 9 = 36 and 4+9 = 5 Step 2: Rewrite 5x with 4x and 9x: 6x2 4x + 9x 6 Step 3: Factor first two and last two: 2x(3x 2) + 3(3x 2) Step 4: Common Factor is (3x 2): (2x+3)(3x 2) Check: (2x+3)(3x 2) = 6x2 4x + 9x 6 = 6x2 + 5x 6 (Yes)This resource was uploaded by: Adrian