# Tutor Hunt Questions

“1. If you write all the numbers from 1 to 100, how many times will the digit 9 appear?

2. How many spots are there altogether on five, normal, six-sided dice?

3. How can you use six nines to make 100?

2. How many spots are there altogether on five, normal, six-sided dice?

3. How can you use six nines to make 100?

8 years ago

Maths Question asked by Zak

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## 5 Answers

#### Accepted Answer

1. 20 times. 9 19 29 39 49 59 69 79 89 90, 91, 92, 93,...,99 . technically if you do not specify whole numbers then infinity.

2. 21 * 5 = 105

3. (9 * 9) + 9 + 9 + (9 / 9) = 100

2. 21 * 5 = 105

3. (9 * 9) + 9 + 9 + (9 / 9) = 100

Answered by Gordon | 8 years ago

We can use simple symmetries instead of brutal force to solve the problems.

Problem 1.

Observe: 00, 01, 02, 03, 04, ... 09, 10, 11, ... 99

The number of appearances for 0 to 9 are symmetric therefore dight 9 appears 2*100/10=20 times

Problem 2.

5*(1+2+3+4+5)=105

Problem 3.

9+9/9=10, therefore (9+9/9)(9+9/9)=100

Thanks

Problem 1.

Observe: 00, 01, 02, 03, 04, ... 09, 10, 11, ... 99

The number of appearances for 0 to 9 are symmetric therefore dight 9 appears 2*100/10=20 times

Problem 2.

5*(1+2+3+4+5)=105

Problem 3.

9+9/9=10, therefore (9+9/9)(9+9/9)=100

Thanks

1) 11 nines will appear.

2) 105 dots will appear.

3) 9x9=81+9+9=99+(9/9)=100

2) 105 dots will appear.

3) 9x9=81+9+9=99+(9/9)=100

Answered by Numan | 8 years ago

A) the digit 9 will appear once on its own

B) 105 as there is 21 on 1 so multiply by 5

C) 9 times 9 = 81

81 + 9 = 90

9 divided 9 = 1

1 + 9 = 10

90 + 10 = 100

B) 105 as there is 21 on 1 so multiply by 5

C) 9 times 9 = 81

81 + 9 = 90

9 divided 9 = 1

1 + 9 = 10

90 + 10 = 100