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Percentage Yield (chemistry Only) (GCSE Chemistry)

The following is a GCSE Chemistry test covering 'Percentage Yield (chemistry Only)' from the broader topic Quantitative Chemistry. The test is geared towards the AQA exam board style syllabus.
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Which calculation gives percentage yield when given moles: theoretical moles = 0.250 mol and actual moles = 0.190 mol?
Hydrogen + chlorine ? hydrogen chloride. Theoretical yield of HCl = 36.5 g; actual yield = 29.2 g. What is percentage yield (to 3 s.f.)?
When calculating theoretical yield you must base the calculation on the limiting reagent. Which statement is correct?
Which laboratory technique helps improve percentage yield by preventing product loss during transfer?
A student reports percentage yield to two significant figures as 87%. Which of these actual calculations is consistent? (theoretical 14.5 g)
A chemist expects theoretical mass 5.00 g. He obtains 4.20 g on first run, repeats protocol identically and obtains 4.25 g. Which value should be used as actual yield when reporting % yield?
You obtain 2.40 g product but after drying it still contains 0.10 g solvent. The theoretical mass is 2.50 g. Which is the correct percentage yield (use dry mass)?
A student obtains very different yields in four repeats (random scatter). Which best practice reduces random error and gives a better percentage yield estimate?
A reaction gives a percentage yield greater than 100%. Which is the most likely reason?
Which of these reasons explains a low percentage yield (e.g., 45%)?
The maximum theoretical mass of a salt is 12.5 g and the percentage yield is 92.8%. Calculate the actual mass of salt produced.