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Percentage Yield (chemistry Only) (GCSE Chemistry)

The following is a GCSE Chemistry test covering 'Percentage Yield (chemistry Only)' from the broader topic Quantitative Chemistry. The test is geared towards the AQA exam board style syllabus.
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When calculating theoretical yield you must base the calculation on the limiting reagent. Which statement is correct?
Calcium carbonate is heated to give calcium oxide. Theoretical mass of CaO = 12.0 g but student obtains 10.0 g. What is the percentage yield (to 3 s.f.)?
Theoretical yield of a product is 12.4 g and the actual mass obtained is 9.3 g. What is the percentage yield (to the nearest whole %)?
If the maximum theoretical mass of a salt is 25.0 g and a student obtains 20.0 g, what is the percentage yield?
A student expects 5.00 g of a product (theoretical) but recovers only 4.50 g. Which experimental factor would directly reduce percentage yield?
A reaction gives a percentage yield greater than 100%. Which is the most likely reason?
The maximum theoretical mass of a salt is 12.5 g and the percentage yield is 92.8%. Calculate the actual mass of salt produced.
Which statement about reporting percentage yield is correct?
A theoretical yield requires calculations using balanced equation. For 2A + 3B ? 4C, if you start with 0.500 mol A and excess B, how many moles of C are theoretically possible?
A student calculates percentage yield using the formula: percentage yield = (mass of product actually obtained / maximum theoretical mass of product) × 100.
When calculating percentage yield using masses, why must you convert masses to moles if reaction equation involves mole ratios?