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I would like to find data from the electrolysis of dilute copper sulphate with products and percentages.

2 years ago

Chemistry Question asked by Jayne

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You will require this equation and also percentage of which product you require.
Cu2+(aq) + 2e- ==> Cu(s) and 4OH-(aq) - 4e- ==> 2H2O(l) + O2(g
From the equation we know

* It takes a transfer of 2 moles of electrons to form 1 mole of solid copper (63.5g) from 1 mole of copper(II) ions, Cu2+


* and a transfer of 4 moles of electrons to form 1 mole of oxygen from 4 moles of hydroxide, OH- ions.





You need to know the atomic weight elements .Cu=63.5O


You also need to know basic fact of electrolysis.Mole fact
*(+) anode and (-) cathode electrode product ratio
If you know how much of a substance is made at one electrode, you can theoretically calculate the amount of substance formed at the other electrode.
Using basic math to find percentage you can work out your


:)
Answered by Zeba | 2 years ago
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