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“I would like to find data from the electrolysis of dilute copper sulphate with products and percentages.
10 years ago
Chemistry Question asked by Jayne
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You will require this equation and also percentage of which product you require.
Cu2+(aq) + 2e- ==> Cu(s) and 4OH-(aq) - 4e- ==> 2H2O(l) + O2(g
From the equation we know
* It takes a transfer of 2 moles of electrons to form 1 mole of solid copper (63.5g) from 1 mole of copper(II) ions, Cu2+
* and a transfer of 4 moles of electrons to form 1 mole of oxygen from 4 moles of hydroxide, OH- ions.
You need to know the atomic weight elements .Cu=63.5O
You also need to know basic fact of electrolysis.Mole fact
*(+) anode and (-) cathode electrode product ratio
If you know how much of a substance is made at one electrode, you can theoretically calculate the amount of substance formed at the other electrode.
Using basic math to find percentage you can work out your
:)
Cu2+(aq) + 2e- ==> Cu(s) and 4OH-(aq) - 4e- ==> 2H2O(l) + O2(g
From the equation we know
* It takes a transfer of 2 moles of electrons to form 1 mole of solid copper (63.5g) from 1 mole of copper(II) ions, Cu2+
* and a transfer of 4 moles of electrons to form 1 mole of oxygen from 4 moles of hydroxide, OH- ions.
You need to know the atomic weight elements .Cu=63.5O
You also need to know basic fact of electrolysis.Mole fact
*(+) anode and (-) cathode electrode product ratio
If you know how much of a substance is made at one electrode, you can theoretically calculate the amount of substance formed at the other electrode.
Using basic math to find percentage you can work out your
:)
Answered by [Deleted Member]
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